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Example · Example 3

Q.Using Laplace's corrected formula, calculate the speed of sound in air at STP, given the pressure P=1.013×105 PaP=1.013\times10^{5}\ \text{Pa}, the density of air ρ=1.29 kg m−3\rho=1.29\ \text{kg m}^{-3}, and γ=1.4\gamma=1.4 for air.

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✓ Free question

Given: P=1.013×105 PaP=1.013\times10^{5}\ \text{Pa}, ρ=1.29 kg m−3\rho=1.29\ \text{kg m}^{-3}, γ=1.4\gamma=1.4.

Using Laplace's formula vL=γP/ρv_L=\sqrt{\gamma P/\rho}:

vL=1.4×1.013×1051.29=1.4182×1051.29=1.0994×105v_L = \sqrt{\frac{1.4\times1.013\times10^{5}}{1.29}} = \sqrt{\frac{1.4182\times10^{5}}{1.29}} = \sqrt{1.0994\times10^{5}}

vL≈331.6 m s−1v_L \approx 331.6\ \text{m s}^{-1}

✓Final answer

Laplace's formula predicts a speed of sound in air at STP of about 331.6 m s−1331.6\ \text{m s}^{-1}, in close agreement with the experimentally measured value of about 332 m s−1332\ \text{m s}^{-1} (Newton's uncorrected isothermal formula would have predicted only about 280 m s−1280\ \text{m s}^{-1}).

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