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Worked Examples · Example 1

Q.Find the EMI for a personal loan of ₹1,20,000, taken at 12% per annum, to be repaid over 12 monthly instalments.

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✓ Free question

Here the loan amount P=₹1,20,000P=₹1{,}20{,}000, the annual rate is 12%12\%, and the tenure is n=12n=12 months.

Step 1 — Convert the annual rate to a monthly rate.

r=1212×100=0.01  (1% per month)r = \frac{12}{12\times100} = 0.01 \;(1\% \text{ per month})

Step 2 — Compute (1+r)n(1+r)^n.

(1.01)12=1.126825(1.01)^{12} = 1.126825

Step 3 — Apply the EMI formula.

EMI=P r (1+r)n(1+r)n−1=1,20,000×0.01×1.1268251.126825−1=1,352.190.126825\text{EMI} = \frac{P\,r\,(1+r)^{n}}{(1+r)^{n}-1} = \frac{1{,}20{,}000\times0.01\times1.126825}{1.126825-1} = \frac{1{,}352.19}{0.126825}

Step 4 — Evaluate.

EMI≈₹10,661.85 per month (rounded to the nearest paisa)\text{EMI} \approx ₹10{,}661.85 \text{ per month (rounded to the nearest paisa)}

✓Final answer

The EMI on this personal loan is approximately ₹10,661.85 per month.

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