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Worked Examples · Example 4

Q.A borrower pays an EMI of ₹21,116.42 per month for 10 months on a loan taken at 12% per annum. Find the loan amount.

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Here EMI=₹21,116.42\text{EMI}=₹21{,}116.42, annual rate 12%12\% so monthly rate r=0.01r=0.01, tenure n=10n=10 months, and the loan amount PP is unknown.

Step 1 — Compute (1+r)n(1+r)^n.

(1.01)10=1.104622(1.01)^{10} = 1.104622

Step 2 — Rearrange the EMI formula for PP.

P=EMI×(1+r)n−1r(1+r)n=21,116.42×1.104622−10.01×1.104622P = \text{EMI}\times\frac{(1+r)^{n}-1}{r(1+r)^{n}} = 21{,}116.42\times\frac{1.104622-1}{0.01\times1.104622}

Step 3 — Evaluate. …

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