Mathematics · Ch 5 — Continuity and Differentiability
Logarithmic Differentiation
Logarithmic Differentiation
The problem this technique solves. None of the differentiation rules developed so far
directly handle a function of the form , where both the base and the
exponent are themselves functions of -- for instance, . The power rule
requires a constant exponent ; the exponential rule
requires a constant base . In , neither is constant, so
neither rule applies as it stands. Logarithmic differentiation resolves exactly this
situation, by using the property (Section 6) to move the variable exponent down
into an ordinary product, which the chain and product rules can then handle.
Method (variable base and exponent). Given with :
- Take the natural logarithm of both sides: .
- Differentiate both sides with respect to , using implicit differentiation on the left (since is a function of : , by the chain rule of Section 3) and the product rule on the right:
- Multiply both sides by to isolate .
Worked illustration (, ). Here . Taking logs: .
Differentiating (product rule on the right, since both factors depend on ):
Multiplying back by :
matching Example 7.
A second, equally important use: products and quotients of several factors. Even when the
exponents are all constant, logarithmic differentiation turns a lengthy product or quotient --
which would otherwise need repeated applications of the product and quotient rules, with a high
chance of a sign or term-dropping slip -- into a sum of simple logarithmic terms, each
differentiated independently. For (each
a function of ), taking logs gives
so, differentiating term by term,
When to reach for logarithmic differentiation. Two clear signals: (i) the function has a
variable raised to a variable power (like , , ), where no ordinary …