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Mathematics · Ch 5 — Continuity and Differentiability

Parametric Differentiation

9

Parametric Differentiation

Parametric form. Sometimes xx and yy are both expressed in terms of a third, independent

variable tt (the parameter), rather than one being written directly as a function of the

other:

x=f(t),y=g(t).x=f(t), \qquad y=g(t).

As tt varies, the point (x,y)=(f(t),g(t))(x,y)=(f(t),g(t)) traces out a curve in the plane. Common examples

include x=acos⁡θ, y=asin⁡θx=a\cos\theta,\ y=a\sin\theta (a circle of radius aa, parameter θ\theta) and

x=at2, y=2atx=at^2,\ y=2at (a parabola, parameter tt).

Finding dy/dxdy/dx. Provided x=f(t)x=f(t) and y=g(t)y=g(t) are both differentiable functions of tt, and

dx/dt≠0dx/dt\neq0, the chain rule (Section 3) gives

dydt=dydx⋅dxdt⟹dydx=dy/dtdx/dt,\frac{dy}{dt} = \frac{dy}{dx}\cdot\frac{dx}{dt} \quad\Longrightarrow\quad \frac{dy}{dx} = \frac{dy/dt}{dx/dt},

by dividing through by dx/dtdx/dt. In words: differentiate yy and xx separately with respect

to the parameter tt, then take the ratio -- never differentiate yy with respect to xx

directly when only the parametric equations are given, and never attempt to eliminate tt and

find an explicit y=h(x)y=h(x) unless the elimination is genuinely straightforward (it frequently is

not).

Worked illustration (x=at2, y=2atx=at^2,\ y=2at, a parabola).

dxdt=2at,dydt=2a,\frac{dx}{dt} = 2at, \qquad \frac{dy}{dt} = 2a,

so

dydx=2a2at=1t,t≠0,\frac{dy}{dx} = \frac{2a}{2at} = \frac{1}{t}, \qquad t\neq0,

matching Example 8 -- the slope of the parabola y2=4axy^2=4ax at the point corresponding to parameter

tt.

A second illustration (x=acos⁡θ, y=bsin⁡θx=a\cos\theta,\ y=b\sin\theta, an ellipse).

dxdθ=−asin⁡θ,dydθ=bcos⁡θ,\frac{dx}{d\theta} = -a\sin\theta, \qquad \frac{dy}{d\theta} = b\cos\theta,

so

dydx=bcos⁡θ−asin⁡θ=−bacot⁡θ.\frac{dy}{dx} = \frac{b\cos\theta}{-a\sin\theta} = -\frac{b}{a}\cot\theta.

Why this matters beyond convenience. Many curves that are natural to describe with a

parameter -- circles, ellipses, cycloids, projectile trajectories with tt as time -- either have …