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Example · Example 4

Q.Verify that y=Asin⁡x+Bcos⁡xy = A\sin x + B\cos x, where A,BA, B are arbitrary constants, is the general solution of d2ydx2+y=0\dfrac{d^2y}{dx^2} + y = 0.

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Given y=Asin⁡x+Bcos⁡xy = A\sin x + B\cos x. Differentiating,

y′=Acos⁡x−Bsin⁡x,y′′=−Asin⁡x−Bcos⁡x=−(Asin⁡x+Bcos⁡x)=−y.y' = A\cos x - B\sin x, \qquad y'' = -A\sin x - B\cos x = -(A\sin x+B\cos x) = -y.

So y′′=−yy'' = -y, i.e. y′′+y=0y'' + y = 0 for every choice of the constants A,BA,B and every xx -- the given function satisfies the differential equation identically, so it is a solution. …

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