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Exercise: Elementary Properties and S... · Q21

Q.Prove that cos⁡−1(−x)=π−cos⁡−1x\cos^{-1}(-x)=\pi-\cos^{-1}x for x∈[−1,1]x\in[-1,1], and use it to find cos⁡−1 ⁣(−12)\cos^{-1}\!\left(-\dfrac12\right).

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✓ Free question

Proof of the identity. Let y=cos⁡−1xy=\cos^{-1}x, so x=cos⁡yx=\cos y with y∈[0,π]y\in[0,\pi]. Then −x=−cos⁡y=cos⁡(π−y)-x=-\cos y=\cos(\pi-y), and since y∈[0,π]y\in[0,\pi], so is π−y\pi-y. Hence π−y\pi-y is the principal value of cos⁡−1(−x)\cos^{-1}(-x):

cos⁡−1(−x)=π−y=π−cos⁡−1x.\cos^{-1}(-x)=\pi-y=\pi-\cos^{-1}x.

Application (x=1/2x=1/2): cos⁡−1 ⁣(−12)=π−cos⁡−1 ⁣(12)=π−π3=2π3\cos^{-1}\!\left(-\dfrac12\right)=\pi-\cos^{-1}\!\left(\dfrac12\right)=\pi-\dfrac{\pi}{3}=\dfrac{2\pi}{3}.

✓Final answer

cos⁡−1 ⁣(−12)=2π3\cos^{-1}\!\left(-\frac12\right)=\frac{2\pi}{3}

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