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Exercise: Graphs · Q17

Q.Describe the graph of y=tan⁡−1xy=\tan^{-1}x, stating its domain, range and behaviour as x→±∞x\to\pm\infty.

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✓ Free question

The graph of y=tan⁡−1xy=\tan^{-1}x has domain all of R\mathbb{R} and range the open interval (−π2,π2)\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right). It is strictly increasing throughout, passes through the origin (since tan⁡−10=0\tan^{-1}0=0), and has two horizontal asymptotes: y→π2y\to\dfrac{\pi}{2} as x→∞x\to\infty, and y→−π2y\to-\dfrac{\pi}{2} as x→−∞x\to-\infty -- the curve gets arbitrarily close to these lines but never touches them, since the range is open. This gives it the characteristic S-shape of a bounded, monotonic function with unbounded domain.

✓Final answer

Increasing S-shaped curve through the origin, bounded between y=−π/2y=-\pi/2 and y=π/2y=\pi/2, approached but never reached as x→∓∞x\to\mp\infty

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