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Question 51 of 59

Q.Find the acute angle between the lines whose direction ratios are 2, 1, -2 and 3, -4, 5.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2024Subjective· 2mImportance★★★★★
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Use the direction-ratio formula cos⁡θ=∣a1a2+b1b2+c1c2∣a12+b12+c12a22+b22+c22\cos\theta = \dfrac{|a_1a_2+b_1b_2+c_1c_2|}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}.

Given direction ratios (2,1,−2)(2,1,-2) and (3,−4,5)(3,-4,5), the acute angle θ\theta between the lines satisfies:

cos⁡θ=∣2(3)+1(−4)+(−2)(5)∣22+12+(−2)2⋅32+(−4)2+52\cos\theta = \frac{|2(3)+1(-4)+(-2)(5)|}{\sqrt{2^2+1^2+(-2)^2}\cdot\sqrt{3^2+(-4)^2+5^2}}

Numerator: ∣6−4−10∣=∣−8∣=8|6-4-10| = |-8| = 8.

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