Q.Define the term 'angle of dip'. The horizontal component of the earth's magnetic field at a place is B and angle of dip is 60°. What is the value of vertical component of the earth's magnetic field at that place? OR The electron in the hydrogen atom circles around the proton with a speed of 2.18×10^6 m/s in an orbit of radius 5.3×10^-11 m. What is the equivalent dipole moment?

The angle of dip satisfies tan θ = (vertical component)/(horizontal component) = V/H. Given V = 2H, tan θ = 2. Option (a).

Step 1 — definition of dip: the vertical component V and horizontal component H of the Earth's magnetic field are related to the dip angle θ by tan θ = V/H (NCERT …

The angle of dip relates H and V by tan(dip) = V/H; substituting 60° gives H/V = 1/√3.

The angle of dip $\delta$ at a place is defined by:

$\tan\delta = \dfrac{V}{H}$

where $V$ and $H$ are the vertical and horizontal components of the Earth's magnetic field.

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