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Worked Examples · Example 2

Q.The marks obtained by 50 first-year Commerce students in an Economics test are grouped as follows: 0–10: 5 students, 10–20: 8 students, 20–30: 15 students, 30–40: 12 students, 40–50: 10 students. Calculate the arithmetic mean using the step-deviation method, and verify your answer using the direct method.

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✓ Free question

Step 1 — Set up mid-values and step deviations. Class width h=10h=10; take assumed mean A=25A=25 (mid-value of the 20–30 class).

ClassMid-value (m)fd′ = (m−A)/hf·d′
0–1055−2−10
10–20158−1−8
20–30251500
30–403512112
40–504510220
TotalN = 50Σfd′ = 14

Step 2 — Apply the step-deviation formula.

Xˉ=A+Σfd′N×h=25+1450×10=25+2.8=27.8\bar X = A + \frac{\Sigma fd'}{N}\times h = 25 + \frac{14}{50}\times 10 = 25 + 2.8 = 27.8

Step 3 — Verify by the direct method.

Σfm=(5×5)+(8×15)+(15×25)+(12×35)+(10×45)=25+120+375+420+450=1390\Sigma fm = (5\times5)+(8\times15)+(15\times25)+(12\times35)+(10\times45) = 25+120+375+420+450 = 1390

Xˉ=ΣfmN=139050=27.8\bar X = \frac{\Sigma fm}{N} = \frac{1390}{50} = 27.8

Both methods agree exactly.

✓Final answer

Arithmetic Mean = 27.8 marks (confirmed by both the step-deviation and direct methods).

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