Skip to content
NCERT Exemplar · Q19

Q.3CO2 + 9ATP + 6NADPH + Water → glyceraldehyde 3 – phosphate + 9 ADP + 6 NADP+ + 8 Pi. Analyze the above reaction and answer the following questions: a. How many molecules of ATP & NADPH are required to fix one molecule of CO2? b. Where in the chloroplast does this process occur?

Yanam BieapShortImportance★★★★★est
44% · 28/63 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The given equation is the Calvin cycle's net reaction for one turn; scaling it down shows 3 ATP and 2 NADPH are consumed per CO2 fixed, and the whole process happens in the chloroplast's stroma.

a. ATP and NADPH per CO2: The equation shows 3 molecules of CO2 being fixed using 9 molecules of ATP and 6 molecules of NADPH to produce one molecule of glyceraldehyde 3-phosphate. Dividing these quantities by the 3 CO2 molecules fixed gives the requirement per single CO2: 9 ATP ÷ 3 = 3 ATP, and 6 NADPH ÷ 3 = 2 NADPH. This is exactly the ratio described for the Calvin cycle as a whole — every CO2 molecule that enters the cycle requires 3 ATP and 2 NADPH across its three stages (carboxylation, reduction and regeneration), with two of the three ATP and both NADPH used in the reduction stage and the remaining one ATP used in regenerating the CO2 acceptor RuBP. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.