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Exercise 5.1 · Q25

Q.The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side.

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The problem uses the perimeter condition to set up an inequality in terms of the shortest side. By letting the shortest side be xx, expressing the other sides in terms of xx, and applying the "perimeter ≥ 61" condition, we find the minimum length of the shortest side is 9 cm.


The key here is to translate the word problem into a single inequality. The perimeter is a sum of three sides, and we are told how they relate to each other. Once we express everything in terms of one variable, the inequality gives us a lower bound.

Let the shortest side be xx cm. Then:

  • Longest side = 3x3x (three times the shortest).
  • Third side = 3x−23x - 2 (2 cm shorter than the longest).

The perimeter is the sum:

x+3x+(3x−2)=7x−2x + 3x + (3x - 2) = 7x - 2

We are told the perimeter is at least 61 cm. That means:

7x−2≥617x - 2 \geq 61

Now solve:

  1. Add 2 to both sides: 7x≥637x \geq 63
  2. Divide by 7: x≥9x \geq 9

Since xx is the shortest side, the minimum possible length is 9 cm. …

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