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Worked Examples · Example 5

Q.Find the equation of the line through (−2,3)(-2, 3) with slope −4-4.

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The key idea is to use the point-slope form of a line: given a point (x1,y1)(x_1, y_1) and slope mm, the equation is y−y1=m(x−x1)y - y_1 = m(x - x_1). Substituting (−2,3)(-2, 3) and m=−4m = -4 gives y=−4x−5y = -4x - 5.

Why point-slope form?

When you know a line’s slope and one point it passes through, you can immediately write its equation. The slope tells you how the line tilts — for every 1 unit you move right, you move mm units up (or down if mm is negative). The point anchors the line at a specific location.

The point-slope formula y−y1=m(x−x1)y - y_1 = m(x - x_1) is just a direct translation of that idea: the vertical change from the known point equals the slope times the horizontal change. No memorisation of intercepts needed.

Step-by-step

  1. Identify the given values.

    The point is (−2,3)(-2, 3), so x1=−2x_1 = -2 and y1=3y_1 = 3. The slope is m=−4m = -4.

  2. Plug into the point-slope form.

y−3=−4(x−(−2))y - 3 = -4(x - (-2))

Notice the double negative: x−(−2)x - (-2) becomes x+2x + 2.

  1. Simplify the right-hand side.

y−3=−4(x+2)y - 3 = -4(x + 2)

Distribute the −4-4:

y−3=−4x−8y - 3 = -4x - 8

  1. Solve for yy to get slope-intercept form. Add 3 to both sides: …

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