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Exercise 9.2 · Q19

Q.By using the concept of equation of a line, prove that the three points (3,0)(3, 0), (−2,−2)(-2, -2) and (8,2)(8, 2) are collinear.

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The three points are collinear because the slope between any two pairs is the same (25\frac{2}{5}), meaning they all lie on the same straight line. The equation of the line through (3,0)(3,0) and (−2,−2)(-2,-2) is 2x−5y=62x - 5y = 6, and (8,2)(8,2) satisfies it.

Why the Equation of a Line Proves Collinearity

Three points are collinear if they all lie on one straight line. The cleanest way to prove this using the concept of a line is to pick any two points, find the equation of the line passing through them, and then check whether the third point satisfies that equation. If it does, all three are on the same line.

This works because a line is uniquely determined by any two distinct points. So if the third point obeys the same linear relation, it must lie on that same line.

Step-by-Step Proof

1. Choose two points to define the line.

Let’s take A(3,0)A(3, 0) and B(−2,−2)B(-2, -2). We’ll find the equation of line ABAB.

2. Find the slope of ABAB.

The slope mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

Here:

m=−2−0−2−3=−2−5=25m = \frac{-2 - 0}{-2 - 3} = \frac{-2}{-5} = \frac{2}{5}

Tip

Slope is the rate at which yy changes per unit change in xx. A common slope between two different pairs of points is the hallmark of collinearity.

3. Write the equation of the line using point-slope form.

Using point A(3,0)A(3, 0):

y−0=25(x−3)y - 0 = \frac{2}{5}(x - 3)

Multiply through by 5:

5y=2(x−3)5y = 2(x - 3)

5y=2x−65y = 2x - 6

Rearrange to standard form:

2x−5y=62x - 5y = 6

The equation of the line through (3,0)(3,0) and (−2,−2)(-2,-2) is:

2x−5y=62x - 5y = 6 …

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