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Worked Examples · Example 12.5

Q.A flask contains argon and chlorine in the ratio of 2:12:1 by mass. The temperature of the mixture is 27 ∘C27\ ^\circ\text{C}. Obtain the ratio of

(i) average kinetic energy per molecule, and
(ii) root mean square speed vrmsv_{rms} of the molecules of the two gases. Atomic mass of argon =39.9 u= 39.9\ \text{u}; Molecular mass of chlorine =70.9 u= 70.9\ \text{u}.
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For a gas mixture at the same temperature, every molecule has the same average kinetic energy regardless of mass, so the ratio is 1:11:1. The rms speed ratio follows from vrms∝1/Mv_{rms} \propto 1/\sqrt{M}, giving vrms,Ar:vrms,Cl2≈1.33:1v_{rms,\text{Ar}} : v_{rms,\text{Cl}_2} \approx 1.33 : 1.

The Kinetic Theory of Gases gives us a clean, physical picture. Temperature is a measure of the average translational kinetic energy of molecules — not their speed. At the same temperature, every molecule in a mixture, regardless of its mass or identity, has the same average kinetic energy. That’s the key insight for part (i).

For part (ii), since kinetic energy is 12mvrms2\frac12 m v_{rms}^2, if two molecules have the same kinetic energy but different masses, their rms speeds must differ. Heavier molecules move slower on average. The relation is vrms=3kT/mv_{rms} = \sqrt{3kT/m}, so vrms∝1/mv_{rms} \propto 1/\sqrt{m}.

Let’s work it out step by step.


  1. Average kinetic energy per molecule From kinetic theory, the average translational kinetic energy of a molecule is

⟨K⟩=32kBT\langle K \rangle = \frac{3}{2} k_B T

This depends only on temperature, not on the mass or type of molecule. Since both gases are at the same temperature (27∘C=300 K27^\circ\text{C} = 300\ \text{K}), every argon atom and every chlorine molecule has the same ⟨K⟩\langle K \rangle.

Therefore, the ratio is

⟨K⟩Ar⟨K⟩Cl2=1:1\frac{\langle K \rangle_{\text{Ar}}}{\langle K \rangle_{\text{Cl}_2}} = 1:1

  1. Root mean square speed The rms speed is given by

vrms=3kBTmv_{rms} = \sqrt{\frac{3k_B T}{m}}

where mm is the mass of one molecule. Since kBk_B and TT are the same for both,

vrms∝1mv_{rms} \propto \frac{1}{\sqrt{m}}

So the ratio of rms speeds is the inverse square root of the ratio of molecular masses.

We need the mass of a single molecule. Using atomic mass units:

  • Argon: MAr=39.9 uM_{\text{Ar}} = 39.9\ \text{u} per atom
  • Chlorine: MCl2=70.9 uM_{\text{Cl}_2} = 70.9\ \text{u} per molecule

The mass of one molecule is proportional to its molecular mass in u, so …

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