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NCERT Exemplar · Q15

Q.The volume of a given mass of a gas at 27°C, 1 atm is 100 cc. What will be its volume at 327°C?

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This problem applies Charles's Law, which states that for a fixed mass of gas at constant pressure, its volume is directly proportional to its absolute temperature. By converting the given Celsius temperatures to Kelvin, we find that the volume of the gas at 327∘C327^\circ\text{C} will be 200 cc\boxed{200 \text{ cc}}.

The behavior of gases under changing conditions of temperature, pressure, and volume is fundamentally explained by the Kinetic Theory of Gases. This theory postulates that gases consist of a large number of tiny particles (atoms or molecules) that are in constant, random motion.

When we increase the temperature of a gas, we are essentially increasing the average kinetic energy of these particles. This means the particles move faster and collide with the walls of their container more frequently and with greater force.

If the pressure is to remain constant (as implied in this problem, since the initial pressure is 1 atm and no change in pressure is mentioned for the final state), the volume of the gas must expand. This expansion allows the particles to travel further before hitting a wall, reducing the frequency of collisions per unit area and thus maintaining the original pressure despite the increased force of individual collisions. This direct relationship between volume and temperature (at constant pressure and mass) is known as Charles's Law.

Important

Charles's Law is only valid when temperature is expressed on an absolute scale, like Kelvin. This is because the Kelvin scale directly relates to the average kinetic energy of gas particles, where 0 K0 \text{ K} represents the theoretical point of zero kinetic energy. Using Celsius would lead to incorrect results because it's an arbitrary scale where 0∘C0^\circ\text{C} does not correspond to zero kinetic energy.

Let's apply this understanding to solve the problem.

  1. Identify the given information and the unknown:

    We are given the initial conditions of the gas:

    • Initial temperature, T1=27∘CT_1 = 27^\circ\text{C}
    • Initial pressure, P1=1 atmP_1 = 1 \text{ atm}
    • Initial volume, V1=100 ccV_1 = 100 \text{ cc}

    We are asked to find the final volume (V2V_2) under new conditions:

    • Final temperature, T2=327∘CT_2 = 327^\circ\text{C}
    • Final pressure, P2=1 atmP_2 = 1 \text{ atm} (since no change in pressure is mentioned, we assume it remains constant)
    • The mass of the gas is also constant ("a given mass of a gas").
  2. Convert temperatures to the absolute Kelvin scale:

    As discussed, gas laws require temperatures to be in Kelvin. We convert Celsius to Kelvin by adding 273 (for exam purposes, 273.15 is more precise but 273 is usually sufficient).

    • T1=27∘C+273=300 KT_1 = 27^\circ\text{C} + 273 = 300 \text{ K}
    • T2=327∘C+273=600 KT_2 = 327^\circ\text{C} + 273 = 600 \text{ K}
    Watch out

    A very common mistake is to use Celsius temperatures directly in gas law calculations. Always convert to Kelvin first! …

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