Niobium crystallises in body-centred cubic structure. If density is 8.55 g cm$^{-3}$, calculate atomic radius of niobium using its atomic mass 93 u.

Niobium crystallises in body-centred cubic structure. If density is 8.55 g cm⁻³, calculate atomic radius of ni

Exercises · 1.13

^{-3}

Yanam BieapTextbookSubjectiveImportance★★★★★est

33% · 18/54 Questions

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Step 1 – Edge length from density.

a^3 = \frac{zM}{d\,N_A} = \frac{2\times 93}{8.55\times 6.022\times10^{23}} = \frac{186}{5.149\times10^{24}} = 3.612\times10^{-23}\text{ cm}^3

Step 2 – Take the cube root.

a = (3.612\times10^{-23})^{1/3} = 3.307\times10^{-8}\text{ cm} = 330.7\text{ pm}

Step 3 – Radius for bcc (atoms touch along body diagonal). …