Q.Find the eccentricity of the ellipse $3x^2+4y^2=12$.

Divide through by 12 to reach standard form, identify $a^2$ (the larger denominator) and $b^2$, then substitute into the eccentricity formula.

$3x^2+4y^2=12\ \Rightarrow\ \dfrac{x^2}{4}+\dfrac{y^2}{3}=1$

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