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Mathematics · Ch 9 — Probability

Multiplication Theorem on Probability

9.3

Multiplication Theorem on Probability

13.3 Multiplication Theorem on Probability

When two events EE and FF belong to the same sample space SS, the event that both occur is denoted E∩FE \cap F, often written EFEF. For instance, drawing two cards one after another, we might want the probability of getting a king and a queen — that is P(EF)P(EF).

The multiplication theorem computes P(E∩F)P(E \cap F) using conditional probabilities. From the definition of conditional probability,

P(E∣F)=P(E∩F)P(F),P(F)≠0P(E|F) = \frac{P(E \cap F)}{P(F)}, \quad P(F) \neq 0

we rearrange to get:

P(E∩F)=P(F)⋅P(E∣F)…(1)P(E \cap F) = P(F) \cdot P(E|F) \quad \ldots (1)

Similarly, since E∩F=F∩EE \cap F = F \cap E,

P(F∣E)=P(E∩F)P(E),P(E)≠0  ⟹  P(E∩F)=P(E)⋅P(F∣E)…(2)P(F|E) = \frac{P(E \cap F)}{P(E)}, \quad P(E) \neq 0 \implies P(E \cap F) = P(E) \cdot P(F|E) \quad \ldots (2)

Combining (1) and (2) gives the multiplication rule of probability:

P(E∩F)=P(E)⋅P(F∣E)=P(F)⋅P(E∣F)P(E \cap F) = P(E) \cdot P(F|E) = P(F) \cdot P(E|F)

provided P(E)≠0P(E) \neq 0 and P(F)≠0P(F) \neq 0.

This rule is the foundation for finding probabilities of sequential or simultaneous events when they are not independent.


Multiplication rule for more than two events

The rule extends to three or more events. For three events EE, FF, GG:

P(E∩F∩G)=P(E)⋅P(F∣E)⋅P(G∣EF)P(E \cap F \cap G) = P(E) \cdot P(F|E) \cdot P(G|EF)

The pattern: multiply the probability of the first event, then the conditional probability of each later event given all the previous ones. For nn events:

P(E1∩E2∩⋯∩En)=P(E1)⋅P(E2∣E1)⋅P(E3∣E1E2)⋯P(En∣E1E2⋯En−1)P(E_1 \cap E_2 \cap \cdots \cap E_n) = P(E_1) \cdot P(E_2|E_1) \cdot P(E_3|E_1E_2) \cdots P(E_n|E_1E_2\cdots E_{n-1}) …