A random variable X has the probability distribution X:0,1,2; P(X):k,2k,3k. Find k.

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Every valid probability distribution sums to 1, so add the three probabilities and solve for $k$ .

$k+2k+3k=1$ …

Q.A random variable XXX has the probability distribution X: 0, 1, 2X:\ 0,\,1,\,2X: 0,1,2; P(X): k, 2k, 3kP(X):\ k,\,2k,\,3kP(X): k,2k,3k. Find kkk.