A random variable X has the probability distribution X:0,1,2,3,4; P(X):0.1,k,2k,2k,k. Find k and the mean of X

Question 5 of 9

X

Yanam BieapSubjective· 4mImportance★★★★★est

56% · 5/9 Questions

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Solve $\sum P(X)=1$ for $k$ first, then substitute back into $\text{Mean}=\sum x_i P(x_i)$ .

$0.1+k+2k+2k+k=1$

$0.1+6k=1$

$6k=0.9$

$k=0.15$

…

Q.A random variable XXX has the probability distribution X: 0, 1, 2, 3, 4X:\ 0,\,1,\,2,\,3,\,4X: 0,1,2,3,4; P(X): 0.1, k, 2k, 2k, kP(X):\ 0.1,\,k,\,2k,\,2k,\,kP(X): 0.1,k,2k,2k,k. Find kkk and the mean of XXX.