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Q.If 1,1,α1, 1, \alpha are the roots of x3−6x2+9x−4=0x^3 - 6x^2 + 9x - 4 = 0, then find α\alpha.

Yanam BieapBIEAP Intermediate Board 2018Subjective· 2mImportance★★★★★
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Use the relation between roots and coefficients (sum of roots) of the cubic to find α\alpha.

For a cubic x3+bx2+cx+d=0x^3+bx^2+cx+d=0, the sum of the roots equals −b-b. Here x3−6x2+9x−4=0x^3-6x^2+9x-4=0, so b=−6b=-6, and:

sum of roots=−(−6)=6\text{sum of roots} = -(-6) = 6

The roots are 1,1,α1,1,\alpha, so:

1+1+α=6  ⇒  α=41+1+\alpha = 6 \;\Rightarrow\; \alpha = 4 …

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