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Q.An electron is accelerated through a potential difference VV. Write the expression for its final speed, if it was initially at rest.

Yanam BieapCBSE Class XII Board 2018Subjective· 1mImportance★★★★★
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Using energy conservation eV=12mv2eV=\tfrac12 mv^2, the final speed is v=2eV/mv=\sqrt{2eV/m}.

Concept. When a charge ee is accelerated through a potential difference VV, the electric field does work W=eVW=eV on it. This appears as kinetic energy (a staple of the CBSE Class 12 Physics 2018 board paper).

Why this formula. The work–energy theorem gives Wfield=ΔKEW_{\text{field}}=\Delta KE. Starting from rest, ΔKE=12mv2−0\Delta KE=\tfrac12 mv^2-0.

Step-by-step. …

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