NCERT Exemplar · Q20
Q.A long straight horizontal wire carrying a current of rests fixed on a table. A second straight wire PQ of length and mass carries the same current but in the opposite direction; it is held horizontal and parallel to the fixed wire, directly above it, and is free to move vertically. Because the two currents are anti-parallel they repel, so PQ floats in equilibrium at a height above the fixed wire. Find .
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Start your 14-day free trial to unlock the full solution →Anti-parallel currents repel, so the fixed wire pushes wire PQ upward. In equilibrium this repulsive force equals the weight of PQ. Setting and solving gives .
Concept & formula
Two long parallel wires a distance apart, carrying currents and , exert a force per unit length on each other of
Parallel currents attract; anti-parallel currents (as here) repel. The repulsion on PQ is directed upward and can support its weight.
Step 1 — equilibrium condition
With and length , the total upward force is . It balances the weight of PQ:
Step 2 — solve for
Insert , , , , : …
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