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Worked Examples · Example 13

Q.Pipe A can fill a tank in 20 hours. But due to a leakage it is taking thrice the time to fill the tank. If the tank is full, how long will it take to drain out the tank, If the pipe A is closed?

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The leak steals 130\frac{1}{30} of the tank per hour from pipe A's 120\frac{1}{20}/h fill rate to net 160\frac{1}{60}/h, so the leak alone would empty a full tank in 30 hours.

If a filling pipe's rate is 1n\dfrac1n (tank/hour) and a leak's draining rate is 1x\dfrac1x (tank/hour), the net rate when both act together is

1n−1x=1observed time\dfrac{1}{n} - \dfrac{1}{x} = \dfrac{1}{\text{observed time}}

Given: Pipe A alone fills the tank in n=20n=20 h. With the leak, it takes thrice as long: 3×20=603\times20=60 h.

  1. Rate of pipe A alone: 120\dfrac{1}{20} tank/hour.
  2. Net rate with the leak present (fills in 60 h): 160\dfrac{1}{60} tank/hour.
  3. Let the leak's draining rate be 1x\dfrac{1}{x} tank/hour. Then:

120−1x=160\dfrac{1}{20} - \dfrac{1}{x} = \dfrac{1}{60}

  1. Solve for 1x\dfrac1x: …

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