Skip to content
Exercise 2.1 · Q2

Q.The average of five numbers is 87. If one of the numbers is excluded, then the average gets decreased by 5. Find the excluded number.

Yanam CbseNCERTSubjective· 3mImportance★★★★★est
3% · 2/70 Questions
✓ Free question

Find the total of all 5 numbers, find the new total of the remaining 4 numbers from the reduced average, and subtract to isolate the excluded number.

Sum of observations == Average ×\times Number of observations.

  1. Sum of the original 5 numbers =87×5=435= 87 \times 5 = 435.
  2. After excluding one number, the average decreases by 5, so the new average of the remaining 4 numbers =87−5=82= 87-5 = 82.
  3. Sum of the remaining 4 numbers =82×4=328= 82 \times 4 = 328.
  4. The excluded number == (original sum) −- (sum of remaining 4) =435−328=107= 435-328 = 107.
  5. Self-check: remaining numbers' average =328/4=82= 328/4 = 82, which is exactly 55 less than 8787 ✓.
✓Final answer

The excluded number is 107.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.