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Exercise 6.3 · Q6

Q.How many numbers between 6000 and 7000 formed with the digits 0, 1, 5, 6, 7 and 9 are divisible by 5 if

(i) repetition of digits is allowed
(ii) repetition of digits is not allowed
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Fix the thousands digit as 66 and the units digit as 00 or 55 (divisibility by 5), then count the two middle digits with/without repetition.

Fundamental counting principle; divisibility rule: a number is divisible by 55 iff its last digit is 00 or 55. Digit set: {0,1,5,6,7,9}\{0,1,5,6,7,9\} (6 digits).

Setup: "Between 6000 and 7000" forces the thousands digit =6=6 (1 way, fixed).

(i) Repetition of digits allowed

  1. Thousands digit: 66 (1 way, fixed).
  2. Units digit (must give divisibility by 5): 00 or 55 — 22 ways.
  3. Hundreds digit: any of the 6 given digits (repetition allowed) — 66 ways.
  4. Tens digit: any of the 6 given digits (repetition allowed) — 66 ways.
  5. Total =1×6×6×2=72=1\times6\times6\times2 = 72.

(ii) Repetition of digits not allowed …

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