Skip to content
Exercise 5.2 · Q9

Q.Insert 6 geometric means between 27 and 181\dfrac{1}{81}.

Yanam CbseNCERTSubjective· 2mImportance★★★★★est
27% · 29/106 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

With 6 means inserted, 27 and 181\frac1{81} become the 1st and 8th terms of a G.P.; find rr then the means.

nnth term of a G.P.: tn=arn−1t_n=ar^{n-1}.

  1. Inserting 6 geometric means between 2727 and 181\dfrac1{81} makes an 8-term G.P.: a=27a=27 (1st term), t8=181t_8=\dfrac1{81}.
  2. t8=ar7⇒27r7=181⇒r7=127×81=12187t_8=ar^7\Rightarrow27r^7=\dfrac1{81}\Rightarrow r^7=\dfrac1{27\times81}=\dfrac1{2187}.
  3. Since 2187=372187=3^7, r7=137⇒r=13r^7=\dfrac1{3^7}\Rightarrow r=\dfrac13. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.