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Exercise 3.2 · Q2

Q.Which of the following sets are empty and which are singleton sets?

(i) {x:x is an even prime number}\{x : x \text{ is an even prime number}\}.
(ii) {x:x is a natural number and −1<x<1}\{x : x \text{ is a natural number and } -1 < x < 1\}.
(iii) {x:x is an integer and −1<x<1}\{x : x \text{ is an integer and } -1 < x < 1\}.
(iv) {x:x is a vowel in the word ’EYE’}\{x : x \text{ is a vowel in the word 'EYE'}\}.
(v) {x:x+10=0;x∈N}\{x : x + 10 = 0; x \in N\}.
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✓ Free question

Testing each rule for the number of elements: (i), (iii), (iv) have exactly one element (singleton); (ii) and (v) have none (empty).

[!FORMULA] The empty set ϕ\phi has zero elements; a singleton set has exactly one element.

  1. (i) {x:x even prime}\{x : x \text{ even prime}\}: the only even prime number is 2 (every other even number is divisible by 2 and >2, hence composite). Set ={2}=\{2\}. Singleton.

  2. (ii) {x:x∈N, −1<x<1}\{x : x\in N,\ -1<x<1\}: natural numbers begin at 1, and 11 does not satisfy x<1x<1; no natural number lies strictly between −1-1 and 11. Empty set.

  3. (iii) {x:x∈Z, −1<x<1}\{x : x\in Z,\ -1<x<1\}: the only integer strictly between −1-1 and 11 is 00. Set ={0}=\{0\}. Singleton.

  4. (iv) {x:x is a vowel in ’EYE’}\{x : x \text{ is a vowel in 'EYE'}\}: letters of EYE are E, Y, E; only E is a vowel (Y is not a standard vowel). Set ={E}=\{E\}. Singleton.

  5. (v) {x:x+10=0, x∈N}\{x : x+10=0,\ x\in N\}: solving x+10=0x+10=0 gives x=−10x=-10, which is not a natural number, so no x∈Nx\in N satisfies it. Empty set.

✓Final answer

Singleton sets: (i) {2}\{2\}, (iii) {0}\{0\}, (iv) {E}\{E\}. Empty sets: (ii), (v).

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