Q.Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and A = {1, 3, 5, 7, 9}. Find A′
The complement of a set is everything in the universal set that is not in the original set. Here, .
The idea of a set complement is simple but powerful: it’s the “other half” of the universe. If is the universal set (the collection of all elements we care about), then (read “A complement” or “A prime”) contains every element of that is not in .
Think of it like a Venn diagram: is the entire rectangle, is one circle inside it. is everything outside that circle but still inside the rectangle. So to find , you just scan through and pick out the numbers that are missing from .
Let’s do it step by step.
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List the universal set.
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List the given set .
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Identify what’s missing.
Compare each element of against :
- is in → skip
- is not in → include
- is in → skip
- is not in → include
- is in → skip
- is not in → include
- is in → skip
- is not in → include
- is in → skip
- is not in → include
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Collect the complement.
The elements we kept are . So:
A common mistake is to forget that the complement is defined only with respect to the given universal set . If were different, would change. Here, is clearly given, so we stick to it.
Notice that contains all the odd numbers from , and contains all the even numbers. That’s a neat pattern: complements often reveal a natural partition of the universal set.
The complement of is .
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