Q.State True or False: Let sets and be defined as , . Then .
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Start your 14-day free trial to unlock the full solution →Every multiple of 6 is automatically a multiple of 2, so every element of lies in , making a subset of . The statement is True.
Understanding subset relationships through divisibility
When we say , we mean every element of must also be an element of . The question boils down to: does divisibility by 6 guarantee divisibility by 2?
The key insight is factorization. Since , any integer divisible by 6 must contain both 2 and 3 as factors. In particular, it must be divisible by 2.
Let me make this precise.
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What does contain?
means . Every element can be written as for some integer .
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What does contain?
means . Every element can be written as for some integer .
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Check if every element of belongs to .
Take any . Then for some integer . We can rewrite this as:
Since is an integer (call it ), we have , which means is divisible by 2. Therefore .
- Conclusion from the logic. …
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