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Worked Examples · Example 32

Q.Evaluate without expanding Δ=∣1+a1111+b1111+c∣=abc(1+1a+1b+1c)=abc+ab+bc+ac\Delta = \begin{vmatrix} 1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c \end{vmatrix} = abc\left(1+\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right) = abc+ab+bc+ac.

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Two row subtractions reduce the determinant so that a first-row expansion gives abc+ab+bc+caabc+ab+bc+ca.

Ri→Ri−RjR_i\to R_i-R_j leaves the determinant unchanged; expand a determinant along a row using cofactors.

  1. Δ=∣1+a1111+b1111+c∣.\Delta = \begin{vmatrix} 1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c \end{vmatrix}.

  2. Apply R1→R1−R3R_1\to R_1-R_3 and R2→R2−R3R_2\to R_2-R_3:

Δ=∣a0−c0b−c111+c∣.\Delta = \begin{vmatrix} a & 0 & -c \\ 0 & b & -c \\ 1 & 1 & 1+c \end{vmatrix}.

  1. Expand along R1R_1: Δ=a[b(1+c)−(−c)(1)]−0+(−c)[0⋅1−b⋅1].\Delta = a\big[b(1+c)-(-c)(1)\big] - 0 + (-c)\big[0\cdot1 - b\cdot1\big]. …

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