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Exercise 1 · Q2

Q.Determine the order and degree (if defined) of the differential equation: dydx+ey=0\frac{dy}{dx}+e^y=0

Yanam CbseNCERTSubjective· 2mImportance★★★★★
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✓ Free question

The only derivative is dydx\dfrac{dy}{dx} to the first power; the eye^{y} term does not involve any derivative, so order =1=1 and degree =1=1.

Order = order of the highest derivative. Degree = power of the highest-order derivative when the equation is polynomial in derivatives. Degree is judged from the derivatives only, not from terms such as eye^{y}.

Given: dydx+ey=0\dfrac{dy}{dx}+e^{y}=0.

  1. Highest derivative present is dydx\dfrac{dy}{dx} → order =1=1.
  2. The equation is a polynomial in dydx\dfrac{dy}{dx} (first power); eye^{y} contains no derivative and does not affect the degree → degree =1=1.
✓Final answer

Order =1=1, degree =1=1.

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