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Exercise 1 · Q4

Q.Determine the order and degree (if defined) of the differential equation: (dydx)4+3y(d2ydx2)=0\left(\frac{dy}{dx}\right)^4+3y\left(\frac{d^2y}{dx^2}\right)=0

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The highest derivative is d2ydx2\dfrac{d^2y}{dx^2} (second order), appearing to the first power, so order =2=2 and degree =1=1 (the fourth power is on the first-order derivative, which does not set the degree).

Order = order of the highest derivative. Degree = power of the highest-order derivative (not of a lower-order one) when the equation is polynomial in derivatives.

Given: (dydx)4+3y(d2ydx2)=0\left(\dfrac{dy}{dx}\right)^{4}+3y\left(\dfrac{d^2y}{dx^2}\right)=0.

  1. Highest derivative present is d2ydx2\dfrac{d^2y}{dx^2} → order =2=2. …

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