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Exercise 5 · Q2

Q.A pipe can fill a cistern in 6 hours. Due to a leakage in the tank the cistern is just full in 9 hours. How much time the leakage will take to empty the tank?

Yanam CbseNCERTSubjective· 2mImportance★★★★★
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✓ Free question

The leak rate is the fill rate minus the observed (slower) net rate; its reciprocal is 1818 hours.

Net rate == fill rate −- leak rate, i.e. 16−1L=19\dfrac{1}{6} - \dfrac{1}{L} = \dfrac{1}{9}, where LL is the time the leak takes to empty the full tank.

  1. Pipe's fill rate =16= \dfrac{1}{6} tank/h; with the leak the net rate =19= \dfrac{1}{9} tank/h.
  2. Leak rate =16−19= \dfrac{1}{6} - \dfrac{1}{9}. LCD =18= 18: =318−218=118= \dfrac{3}{18} - \dfrac{2}{18} = \dfrac{1}{18} tank/h.
  3. Time for the leak to empty the full tank =11/18=18= \dfrac{1}{1/18} = 18 hours.

Check: net =16−118=3−118=218=19= \tfrac16 - \tfrac{1}{18} = \tfrac{3-1}{18} = \tfrac{2}{18} = \tfrac19 ✓.

✓Final answer

The leakage will take 1818 hours to empty the tank.

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