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NCERT Exemplar · Q28

Q.Differentiate w.r.t. xx: log⁡[log⁡(log⁡x5)]\log\left[\log(\log x^5)\right].

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The derivative of log⁡[log⁡(log⁡x5)]\log[\log(\log x^5)] is found by applying the chain rule three times in succession. The final result is 5xlog⁡x5⋅log⁡(log⁡x5)\frac{5}{x \log x^5 \cdot \log(\log x^5)}.

The key idea here is the chain rule — when you have a function nested inside another function, you differentiate from the outermost layer inward, multiplying the derivatives at each step. This problem has three layers of nesting: the outer log⁡\log, then another log⁡\log, then log⁡(x5)\log(x^5), and finally x5x^5 itself. Each layer is a function of the one below it.

Think of it like peeling an onion: start with the outermost peel (the first log⁡\log), differentiate it, then move to the next layer, and so on, until you reach the innermost x5x^5. At each step, you leave the inner part untouched while differentiating the outer part.

Let’s work through it step by step.

  1. Identify the structure.

    Let y=log⁡[log⁡(log⁡x5)]y = \log\left[\log(\log x^5)\right]. Here, log⁡\log means the natural logarithm (base ee), as is standard in calculus. The innermost part is x5x^5, then log⁡(x5)\log(x^5), then log⁡(log⁡x5)\log(\log x^5), and finally the outermost log⁡\log.

  2. Apply the chain rule — first layer.

    The derivative of log⁡(u)\log(u) with respect to uu is 1u\frac{1}{u}. So, treating u=log⁡(log⁡x5)u = \log(\log x^5), we have:

dydx=1log⁡(log⁡x5)⋅ddx[log⁡(log⁡x5)].\frac{dy}{dx} = \frac{1}{\log(\log x^5)} \cdot \frac{d}{dx}\left[\log(\log x^5)\right].

  1. Second layer — differentiate log⁡(log⁡x5)\log(\log x^5). Now let v=log⁡x5v = \log x^5. Then ddx[log⁡v]=1v⋅dvdx\frac{d}{dx}[\log v] = \frac{1}{v} \cdot \frac{dv}{dx}. So:

ddx[log⁡(log⁡x5)]=1log⁡x5⋅ddx(log⁡x5).\frac{d}{dx}\left[\log(\log x^5)\right] = \frac{1}{\log x^5} \cdot \frac{d}{dx}(\log x^5).

  1. Third layer — differentiate log⁡(x5)\log(x^5). Here, log⁡(x5)=5log⁡x\log(x^5) = 5 \log x (using the logarithm power rule). Its derivative is:

ddx(log⁡x5)=5x.\frac{d}{dx}(\log x^5) = \frac{5}{x}.

Alternatively, you can use the chain rule directly: derivative of log⁡(x5)\log(x^5) is 1x5⋅5x4=5x\frac{1}{x^5} \cdot 5x^4 = \frac{5}{x}. Same result.

  1. Combine all layers. Multiply everything together: …

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