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NCERT Exemplar · Q20

Q.State whether the following statement is True or False: The equation of a line, which is parallel to 2i^+3j^+k^2\hat{i} + 3\hat{j} + \hat{k} and which passes through the point (5,−2,4)(5, -2, 4), is x−52=y+2−1=z−43\dfrac{x-5}{2} = \dfrac{y+2}{-1} = \dfrac{z-4}{3}.

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The given line equation has direction ratios (2,−1,3)(2, -1, 3), but the required line must be parallel to 2i^+3j^+k^2\hat{i} + 3\hat{j} + \hat{k}, which has direction ratios (2,3,1)(2, 3, 1). Since these are not proportional, the statement is False.

The core idea here is simple: a line's direction is determined by its direction ratios (or direction vector). If two lines are parallel, their direction vectors must be scalar multiples of each other. The given equation claims a specific direction, so we just check whether that direction matches the required one.

Let’s break it down.

  1. What does "parallel to a vector" mean for a line?

    If a line is parallel to a vector v⃗=ai^+bj^+ck^\vec{v} = a\hat{i} + b\hat{j} + c\hat{k}, then the direction ratios of the line are (a,b,c)(a, b, c) — or any scalar multiple of them. So the line we want must have direction ratios proportional to (2,3,1)(2, 3, 1).

  2. What direction does the given equation represent?

    The symmetric form of a line is

x−x0a=y−y0b=z−z0c\frac{x - x_0}{a} = \frac{y - y_0}{b} = \frac{z - z_0}{c}

where (a,b,c)(a, b, c) are the direction ratios. Here, the equation is

x−52=y+2−1=z−43\frac{x-5}{2} = \frac{y+2}{-1} = \frac{z-4}{3}

So the direction ratios claimed are (2,−1,3)(2, -1, 3).

  1. Are (2,−1,3)(2, -1, 3) proportional to (2,3,1)(2, 3, 1)? For two sets of numbers to be proportional, the ratios of corresponding components must be equal. Check:

22=1,−13≠1,31=3\frac{2}{2} = 1, \quad \frac{-1}{3} \neq 1, \quad \frac{3}{1} = 3

Clearly, 1≠−13≠31 \neq -\frac{1}{3} \neq 3. They are not proportional. …

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