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Numerical Problems · Q11

Q.The population of a town was 8,00,000 in 2001 and 9,60,000 in 2011. Calculate the decadal population growth rate.

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✓ Free question

Given: Population in 2001 (Pt−1P_{t-1}) = 8,00,000; Population in 2011 (PtP_t) = 9,60,000.

Formula:

Growth Rate (%)=Pt−Pt−1Pt−1×100\text{Growth Rate (\%)} = \frac{P_t - P_{t-1}}{P_{t-1}} \times 100

Step 1 — Find the absolute increase:

Pt−Pt−1=9,60,000−8,00,000=1,60,000P_t - P_{t-1} = 9,60,000 - 8,00,000 = 1,60,000

Step 2 — Apply the formula:

Growth Rate=1,60,0008,00,000×100=20%\text{Growth Rate} = \frac{1,60,000}{8,00,000} \times 100 = 20\%

Independent verification (cross-check): 8,00,000×1.20=9,60,0008,00,000 \times 1.20 = 9,60,000, which exactly matches the given 2011 figure, confirming the computation.

✓Final answer

The decadal population growth rate is 20%.

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