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Q.Establish a relation between linear acceleration and angular acceleration.

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2018Subjective· 2mImportance★★★★★
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Since linear velocity relates to angular velocity by v=ωrv=\omega r, differentiating with respect to time (radius constant) gives a=rαa=r\alpha.

Consider a particle moving on a circular path of radius rr with angular velocity ω\omega. Its linear (tangential) speed is related to the angular velocity by:

v=ωrv = \omega r

Differentiating both sides with respect to time, noting that rr is constant for a particle on a fixed circular path:

dvdt=rdωdt\frac{dv}{dt} = r\frac{d\omega}{dt}

Since dvdt=a\dfrac{dv}{dt} = a (linear/tangential acceleration) and dωdt=α\dfrac{d\omega}{dt} = \alpha (angular acceleration), this gives:

a=rαa = r\alpha

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