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Q.A car is moving from rest. After 10 seconds its wheels rotate 360 times in 1 minute. If the radius of the wheel is 50 cm, then find - 1) Angular acceleration; 2) Angular velocity after 30 seconds.

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2018Subjective· 2mImportance★★★★★
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The wheel's rpm after 10 s gives its angular velocity there; dividing by 10 s (since it started from rest) gives a constant angular acceleration, which is then used to find ω\omega at t=30t=30 s.

Given: car starts from rest (ω0=0\omega_0=0); after t1=10t_1=10 s the wheel makes 360 rotations per minute; radius of wheel r=50r=50 cm =0.5=0.5 m.

Step 1 — angular velocity at t=10t=10 s:

N=360 rpm=36060 rev/s=6 rev/sN = 360\ \text{rpm} = \frac{360}{60}\ \text{rev/s} = 6\ \text{rev/s}

ω1=2πN=2π×6=12π rad/s≈37.7 rad/s\omega_1 = 2\pi N = 2\pi \times 6 = 12\pi\ \text{rad/s} \approx 37.7\ \text{rad/s}

Step 2 — angular acceleration (uniform, from rest):

α=ω1−ω0t1=12π−010=1.2π rad/s2≈3.77 rad/s2\alpha = \frac{\omega_1-\omega_0}{t_1} = \frac{12\pi - 0}{10} = 1.2\pi\ \text{rad/s}^2 \approx 3.77\ \text{rad/s}^2

Step 3 — angular velocity after t2=30t_2=30 s (from start, same constant α\alpha): …

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