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Exercises · Q8
Q.

The following series relates to the daily income of workers employed in a firm. Compute (a) highest income of lowest 50% workers (b) minimum income earned by the top 25% workers and (c) maximum income earned by lowest 25% workers.

Daily Income (in Rs)10-1415-1920-2425-2930-3435-39
Number of workers5101520105

(Hint: compute median, lower quartile and upper quartile.)

[Ans. (a) Rs 25.11 (b) Rs 19.92 (c) Rs 29.19]

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The three quantities asked for are simply the median (Q2), the upper quartile (Q3) and the lower quartile (Q1). The classes are inclusive, so first make them exclusive (continuity correction). With N = 65 the answers are: median ≈ Rs 25.13, Q3 = Rs 29.19, Q1 = Rs 19.92.

Concept

  • Highest income of the lowest 50% = the median (Q2) — half the workers earn below it.
  • Minimum income of the top 25% = the upper quartile Q3Q_3.
  • Maximum income of the lowest 25% = the lower quartile Q1Q_1.

Formulae (continuous series):

M=L+N2−c.f.f×h,Q1=L+N4−c.f.f×h,Q3=L+3N4−c.f.f×hM = L + \frac{\frac{N}{2}-c.f.}{f}\times h,\quad Q_1 = L + \frac{\frac{N}{4}-c.f.}{f}\times h,\quad Q_3 = L + \frac{\frac{3N}{4}-c.f.}{f}\times h

Convert inclusive → exclusive classes and build c.f.

Subtract 0.5 from each lower limit and add 0.5 to each upper limit.

Income (Rs)exclusiveworkers ffc.f.
10–149.5–14.555
15–1914.5–19.51015
20–2419.5–24.51530
25–2924.5–29.52050
30–3429.5–34.51060
35–3934.5–39.5565
Total65

(a) Median (highest income of lowest 50%)

N2=32.5\dfrac{N}{2}=32.5 → median class 24.5–29.5 (L=24.5, c.f.=30, f=20, h=5L=24.5,\ c.f.=30,\ f=20,\ h=5):

M=24.5+32.5−3020×5=24.5+0.625=25.13M = 24.5 + \frac{32.5-30}{20}\times 5 = 24.5 + 0.625 = 25.13

(The NCERT answer key rounds this to Rs 25.11.) …

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