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Worked Examples · Example 5.1

Q.A balloon is filled with hydrogen at room temperature. It will burst if pressure exceeds 0.2 bar. If at 1 bar pressure the gas occupies 2.27 L volume, upto what volume can the balloon be expanded ?

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Step 1 – Identify the process

Room temperature is constant throughout, so this is an isothermal change of state for a fixed amount of H2_2 gas. Boyle's law applies:

p1V1=p2V2p_1V_1 = p_2V_2

Step 2 – List the data

p1=1 bar,V1=2.27 L,p2=0.2 bar (bursting pressure)p_1 = 1\ \text{bar}, \quad V_1 = 2.27\ \text{L}, \quad p_2 = 0.2\ \text{bar (bursting pressure)}

Step 3 – Solve for V2V_2

V2=p1V1p2=(1 bar)(2.27 L)0.2 barV_2 = \frac{p_1V_1}{p_2} = \frac{(1\ \text{bar})(2.27\ \text{L})}{0.2\ \text{bar}}

V2=11.35 LV_2 = 11.35\ \text{L}

Step 4 – Interpret …

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