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Select Appropriate Alternative · Q5

Q.At constant temperature the pressure of 22.4 dm3 volume of an ideal gas was increased from 105 kPa to 210 kPa, New volume could be- a. 44.8 dm3 b. 11.2dm3 c. 22.4 dm3 d. 5.6dm3

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Step 1. By Boyle's law, at constant temperature P1V1 = P2V2.

Step 2. Given P1 = 105 kPa, V1 = 22.4 dm3, P2 = 210 kPa: V2 = P1V1/P2 = (105 x 22.4)/210 = 2352/210 = 11.2 dm3. …

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