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Q.∫sec⁡xsec⁡x+tan⁡x dx=\int \dfrac{\sec x}{\sec x + \tan x}\,dx =

(a) tan⁡x+sec⁡x+k\tan x + \sec x + k
(b) tan⁡x−sec⁡x+k\tan x - \sec x + k
(c) sec⁡x+k\sec x + k
(d) tan⁡x+k\tan x + k
Bihar BsebBihar Board Intermediate 2021MCQ· 1mImportance★★★★★
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∫sec⁡xsec⁡x+tan⁡x dx=tan⁡x−sec⁡x+k\displaystyle\int \dfrac{\sec x}{\sec x + \tan x}\,dx = \tan x - \sec x + k.

Multiply numerator and denominator by (sec⁡x−tan⁡x)(\sec x - \tan x). Since sec⁡2x−tan⁡2x=1\sec^2 x - \tan^2 x = 1: …

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