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Q.Integrate : ∫cosec⁡xcosec⁡x+cot⁡x dx\displaystyle\int\dfrac{\operatorname{cosec}x}{\operatorname{cosec}x+\cot x}\,dx.

Bihar BsebBihar Board Intermediate 2023Subjective· 2mImportance★★★★★
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Multiply top and bottom by (cosec⁡x−cot⁡x)(\operatorname{cosec}x-\cot x); the denominator becomes 11, leaving ∫(cosec⁡2x−cosec⁡xcot⁡x)dx\int(\operatorname{cosec}^2x-\operatorname{cosec}x\cot x)dx.

Multiply numerator and denominator by (cosec⁡x−cot⁡x)(\operatorname{cosec}x-\cot x). Using cosec⁡2x−cot⁡2x=1\operatorname{cosec}^{2}x-\cot^{2}x=1, the denominator becomes

(cosec⁡x+cot⁡x)(cosec⁡x−cot⁡x)=cosec⁡2x−cot⁡2x=1.(\operatorname{cosec}x+\cot x)(\operatorname{cosec}x-\cot x)=\operatorname{cosec}^{2}x-\cot^{2}x=1.

So the integrand simplifies to

cosec⁡x(cosec⁡x−cot⁡x)=cosec⁡2x−cosec⁡xcot⁡x.\operatorname{cosec}x(\operatorname{cosec}x-\cot x)=\operatorname{cosec}^{2}x-\operatorname{cosec}x\cot x.

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