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Q.Integrate ∫dxx+1+x+2\int \frac{dx}{\sqrt{x+1} + \sqrt{x+2}}.

Bihar BsebBihar Board Intermediate 2024Subjective· 2mImportance★★★★★
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Rationalising the denominator turns the integrand into x+2−x+1\sqrt{x+2}-\sqrt{x+1}, which integrates term by term.

Evaluate ∫dxx+1+x+2\displaystyle\int \dfrac{dx}{\sqrt{x+1}+\sqrt{x+2}}.

Step 1 — multiply numerator and denominator by the conjugate x+2−x+1\sqrt{x+2}-\sqrt{x+1}. The denominator becomes (x+2)−(x+1)=1(x+2)-(x+1)=1.

Step 2 — so the integrand simplifies to x+2−x+1\sqrt{x+2}-\sqrt{x+1}, and the integral is ∫[(x+2)1/2−(x+1)1/2]dx\displaystyle\int\left[(x+2)^{1/2} - (x+1)^{1/2}\right]dx.

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