Skip to content
Question of 373

Q.Integrate: ∫sec⁡xsec⁡x+tan⁡x dx\int \frac{\sec x}{\sec x + \tan x}\,dx.

Bihar BsebBihar Board Intermediate 2025Subjective· 2mImportance★★★★★
0% · 0/373 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Multiply numerator and denominator by (sec⁡x−tan⁡x)(\sec x-\tan x); the denominator becomes 11, leaving sec⁡2x−sec⁡xtan⁡x\sec^2x-\sec x\tan x.

Multiply top and bottom by the conjugate (sec⁡x−tan⁡x)(\sec x - \tan x):

sec⁡xsec⁡x+tan⁡x⋅sec⁡x−tan⁡xsec⁡x−tan⁡x=sec⁡x(sec⁡x−tan⁡x)sec⁡2x−tan⁡2x.\dfrac{\sec x}{\sec x + \tan x}\cdot\dfrac{\sec x - \tan x}{\sec x - \tan x} = \dfrac{\sec x(\sec x - \tan x)}{\sec^2 x - \tan^2 x}.

Since sec⁡2x−tan⁡2x=1\sec^2 x - \tan^2 x = 1, this equals

sec⁡2x−sec⁡x tan⁡x.\sec^2 x - \sec x\,\tan x.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.