Q.Write the solution set of the equation x2+x−2=0 in roster form.
Concept understanding — Interval Notation
Interval Notation: A First Look
Imagine you're describing a range of numbers on the number line. Instead of listing every number (which is impossible — there are infinitely many!), we use a shorthand called interval notation.
🧠 The Intuition: "Between" and "Up To"
Think of a stretch of the number line.
-
Closed interval: "From 2 to 5, including both 2 and 5."
→ You can touch the endpoints.
→ Written as: [2,5]
-
Open interval: "From 2 to 5, not including 2 or 5."
→ The endpoints are "holes" — you can get infinitely close, but not touch.
→ Written as: (2,5)
-
Half-open intervals: "From 2 to 5, including 2 but not 5" (or vice versa).
→ Written as: [2,5) or (2,5]
📐 The Precise Definition
An interval is a set of real numbers between two endpoints.
We use brackets to show whether the endpoint is included.
| Type | Notation | Meaning | Number line picture |
|---|---|---|---|
| Closed | [a,b] | a≤x≤b | ●———● |
| Open | (a,b) | a<x<b | ○———○ |
| Half-open (left) | [a,b) | a≤x<b | ●———○ |
| Half-open (right) | (a,b] | a<x≤b | ○———● |
Key symbols:
[or]= included (closed dot on number line)(or)= not included (open dot on number line)
♾️ Infinite Intervals
What if the range goes on forever? We use the symbol ∞ (infinity).
-
"All numbers greater than 3" → (3,∞)
(3 is not included, and there's no upper bound)
-
"All numbers less than or equal to -1" → (−∞,−1]
(no lower bound, -1 is included)
Important exam rule:
Infinity is always paired with a parenthesis ( or ), never a bracket — because infinity is not a number you can "include."
🧪 Quick Examples
| In words | Interval notation |
|---|---|
| x is between 0 and 10, including both | [0,10] |
| x is greater than -2 | (−2,∞) |
| x is less than or equal to 7 | (−∞,7] |
| x is between -5 and 1, including -5 but not 1 | [−5,1) |
✓ Summary Checklist for Exams
- Smallest number first, then largest.
- Use
[or]when the endpoint is included (≤ or ≥). - Use
(or)when the endpoint is excluded (< or >). - Infinity (∞) always gets a parenthesis.
- The notation [a,b] means all real numbers from a to b, not just integers.
Final tip: Think of the bracket as a fence — if the fence is closed [ you can touch the endpoint; if open ( you cannot. This simple image will save you in exams!
Why this formula?
Interval Notation: Why It Works the Way It Does
Interval notation is a shorthand for describing sets of real numbers that lie between two endpoints. The "why" comes from understanding what the symbols mean in terms of inequalities and the real number line.
1. The Core Idea: Representing a Continuous Range
A real number line is continuous — between any two numbers, there are infinitely many others. Interval notation captures this by specifying:
- Where the interval starts (left endpoint)
- Where it ends (right endpoint)
- Whether the endpoints are included or excluded
The key formulas are just compact translations of inequality statements.
2. The Four Basic Types — Why Each Symbol Is Used
(a) Closed Interval: [a,b]
Inequality form: a≤x≤b
Why the square bracket?
The square bracket [ or ] means "include this endpoint".
- x=a is allowed
- x=b is allowed
- Every number between them is allowed
Derivation:
The set is {x∈R∣a≤x≤b}.
The square bracket visually "closes off" the endpoint — like a fence that includes the post.
(b) Open Interval: (a,b)
Inequality form: a<x<b
Why the parenthesis?
The parenthesis ( or ) means "exclude this endpoint".
- x=a is not allowed
- x=b is not allowed
- Only numbers strictly between are allowed
Derivation:
The set is {x∈R∣a<x<b}.
The parenthesis is like an open circle on the number line — the endpoint is not part of the set.
(c) Half-Open (or Half-Closed) Intervals: [a,b) and (a,b]
Inequality forms:
- [a,b) means a≤x<b
- (a,b] means a<x≤b
Why mixed symbols?
Each endpoint is treated independently:
- Square bracket at the included end
- Parenthesis at the excluded end
Derivation:
These arise naturally when one boundary condition is strict and the other is not. For example, "all numbers from 0 up to but not including 5" is [0,5).
3. Infinite Intervals — Why the Symbol ∞ Gets a Parenthesis
(a,∞) and [a,∞)
Inequality forms:
- (a,∞) means x>a
- [a,∞) means x≥a
Why always a parenthesis at ∞?
∞ is not a real number — it's a concept meaning "unbounded above".
- You cannot "include" infinity because no real number equals infinity
- Therefore, the parenthesis is mandatory: (−∞,b] or (a,∞)
Derivation:
The set {x∈R∣x>a} has no largest element. Writing [a,∞] would falsely suggest ∞ is a number that can be reached.
4. Union of Intervals — Why We Use ∪
When a set consists of separate pieces, we combine intervals with the union symbol ∪.
Example:
All real numbers except x=2 is written as:
(−∞,2)∪(2,∞)
Why not a single interval?
Because there is a gap at x=2. A single interval would incorrectly suggest continuity across that point.
Derivation:
The set is {x∈R∣x<2 or x>2}.
The "or" logically translates to union.
5. Summary Table — The "Why" at a Glance
| Notation | Inequality | Why this symbol? |
|---|---|---|
| [a,b] | a≤x≤b | Both endpoints included (square = closed) |
| (a,b) | a<x<b | Both endpoints excluded (parenthesis = open) |
| [a,b) | a≤x<b | Left included, right excluded |
| (a,∞) | x>a | Infinity is not a number, so always parenthesis |
| (−∞,∞) | All real numbers | Both ends unbounded |
Key Takeaway
Interval notation is inequality notation in visual form:
- Square bracket = "≤" or "≥" (include the endpoint)
- Parenthesis = "<" or ">" (exclude the endpoint)
- Infinity always gets a parenthesis because it's not a real number
- Union (∪) connects separate pieces when there's a gap
Understanding this translation lets you read and write intervals without memorizing — you derive the notation from the inequality every time.
Concept: Solving a Quadratic to Build a Roster-Form Set
To write the solution set of an equation in roster form, first solve the equation, then list every root inside curly braces.
Step 1: Factor the quadratic
x2+x−2=0
Look for two numbers that multiply to −2 and add to 1: these are 2 and −1.
(x+2)(x−1)=0
Step 2: Solve for x
x+2=0⟹x=−2orx−1=0⟹x=1
Step 3: Write the roster form
The solution set contains exactly these two roots.
The solution set in roster form is {−2,1}.
Factoring x2+x−2=0 gives (x+2)(x−1)=0, so x=−2 or x=1. The solution set in roster form is {−2,1}.
Why "roster form" means listing the actual solutions
Roster form describes a set by listing its members directly inside curly braces, separated by commas. When the set in question is "the solution set of an equation," the members ARE the roots of that equation — so writing it in roster form means solving the equation first, then listing every root found.
Step-by-step solution
1. Set up the factoring.
We need x2+x−2=0. To factor a quadratic of the form x2+bx+c, look for two numbers that multiply to c and add to b. Here b=1 and c=−2.
The two numbers are 2 and −1: their product is 2×(−1)=−2 (matches c), and their sum is 2+(−1)=1 (matches b).
2. Write the factored form.
x2+x−2=(x+2)(x−1)
You can check this by expanding: (x+2)(x−1)=x2−x+2x−2=x2+x−2. ✓
3. Apply the zero-product property.
If a product of two factors equals zero, at least one factor must be zero:
x+2=0orx−1=0
x=−2orx=1
4. Collect the roots into roster form.
The solution set is the collection of every value of x that satisfies the equation — here, exactly two values: −2 and 1. Written in roster form:
{−2,1}
Order doesn't matter in a set — {−2,1} and {1,−2} describe the same set. Roster form just needs every element listed once, in any order.
The solution set of x2+x−2=0, in roster form, is {−2,1}.
Method: Roster Form of a Quadratic's Solution Set
Method Name: Factor-Then-List
Why This Works
"The solution set of an equation, in roster form" asks for two things done in sequence: first solve the equation to find every root, then list those roots as the members of a set. The roster form itself is just the final listing step — the real work is solving the equation correctly and completely.
Steps
Step 1: Rearrange into standard form
Make sure the equation reads ax2+bx+c=0 (all terms on one side, set equal to zero).
Step 2: Factor the quadratic
Find two numbers whose product is c (or a×c if a=1) and whose sum is b. Rewrite the quadratic as a product of two linear factors using these numbers.
Step 3: Apply the zero-product property
A product of two factors is zero only if at least one factor is zero. Set each factor equal to zero and solve for x separately.
Step 4: Collect every root
List every distinct value of x found in Step 3 — these are the elements of the solution set.
Step 5: Write the roster form
Enclose the collected roots in curly braces, separated by commas: {root1,root2,…}. Order doesn't matter, but no root should be repeated or omitted.
- CBSE 2026Set ANNUAL1 markMCQQ.Interval form of the set {x:x∈R,−4<x≤6} is(a) [−4,6](b) (−4,6)(c) (−4,6](d) [−4,6)
›Reveal solutionSolution
−4<x means −4 is excluded (open bracket); x≤6 means 6 is included (closed bracket), giving (−4,6].
The set is {x:x∈R, −4<x≤6}. The strict inequality −4<x means the endpoint −4 is not included, written with a round/open bracket '('. The inequality x≤6 means the endpoint 6 is included, written with a square/closed bracket ']'. Combining these gives the interval (−4,6], sometimes called a half-open interval.
✓Final answer(c) (−4,6].
- CBSE 2025Set ANNUAL1 markMCQQ.If A=(2,4) and B=[3,5), then A∩B is(a) (2, 5)(b) [3, 4](c) (3, 4)(d) [3, 4)
›Reveal solutionSolution
Combine the two interval conditions and keep the tighter bound at each end.
We need x satisfying both x∈A=(2,4) and x∈B=[3,5), i.e.
2<x<4and3≤x<5.
Taking the tighter lower bound: since 3≥2, the effective lower bound is x≥3 (from B, inclusive).
Taking the tighter upper bound: since 4≤5, the effective upper bound is x<4 (from A, exclusive).
So A∩B={x:3≤x<4}=[3,4).
✓Final answer(d) [3,4)
- CBSE 2024Set ANNUAL1 markMCQQ.Write {x:x∈R,−8<x≤0} as interval.(a) (−8,10)(b) (−8,0)(c) [−8,0](d) None of these
›Reveal solutionSolution
Translate each inequality into a bracket: strict inequality ⇒ round bracket (open, excluded); ≤ or ≥ ⇒ square bracket (closed, included).
We are given {x:x∈R,−8<x≤0}.
- The left condition is −8<x (strict), so −8 is not included ⇒ open (round) bracket at −8.
- The right condition is x≤0 (non-strict), so 0 is included ⇒ closed (square) bracket at 0.
So the correct interval notation is (−8,0] — open at the left endpoint, closed at the right endpoint.
Checking the options: (a) (−8,10) has the wrong right endpoint;
(b) (−8,0) wrongly excludes 0;
(c) [−8,0] wrongly includes −8. None of them match the genuine mixed-bracket interval (−8,0].
✓Final answer(d) None of these (the correct interval is (−8,0]).
- CBSE 2023Set ANNUAL1 markMCQQ.For the set A={x:x∈R, 3≤x≤4} which one is correct.(a) ]3,4[(b) [3,4](c) [3,4[(d) ]3,4]
›Reveal solutionSolution
A=[3,4]; option (b).
Since x satisfies 3≤x≤4, the endpoints 3 and 4 are included. In interval notation (NCERT Class 11 Sets), a closed interval uses square brackets: [3,4].
✓Final answer(b) [3,4].
- CBSE 2022Set ANNUAL1 markQ.Write the set {x:x∈R, −4<x≤6} as interval.
›Reveal solutionSolution
{x∈R:−4<x≤6}=(−4,6].
A strict inequality (<) uses an open (round) bracket, and a non-strict inequality (≤) uses a closed (square) bracket.
So −4<x≤6 becomes the interval (−4,6].
✓Final answer(−4,6].
- CBSE 2022Set ANNUAL1 markMCQQ.For the set A={x:x∈R, 3≤x≤4} which one is correct(a) [3,4](b) [4,3](c) [3,3](d) None of these
›Reveal solutionSolution
{x∈R:3≤x≤4}=[3,4].
Since both endpoints are included (≤), the interval is closed and written with square brackets, from the smaller value to the larger: [3,4]. (Note [4,3] is invalid as the left number must be smaller.)
Interval notation is introduced in CBSE/NCERT Class 11 Sets.
✓Final answer(a) [3,4].
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