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Exercise 1.3 · Q5

Q.Write the following as intervals :

(i) {x : x ∈ R, – 4 < x ≤ 6}
(ii) {x : x ∈ R, – 12 < x < –10}
(iii) { x : x ∈ R, 0 ≤ x < 7}
(iv) {x : x ∈ R, 3 ≤ x ≤ 4}
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Interval notation is a compact way to write sets of real numbers. The key is to use a round bracket ( for an open endpoint (the number is not included) and a square bracket [ for a closed endpoint (the number is included). The answers are: (i) (−4,6](-4, 6],

(ii) (−12,−10)(-12, -10),

(iii) [0,7)[0, 7),

(iv) [3,4][3, 4].

The Concept: Why Interval Notation Works

When you see a set written like {x:x∈R,−4<x≤6}\{x : x \in \mathbb{R}, -4 < x \leq 6\}, it describes every real number between −4-4 and 66, but with a specific rule at each end. The inequality −4<x-4 < x means −4-4 itself is not part of the set — the set starts just to the right of −4-4. The inequality x≤6x \leq 6 means 66 is included.

Interval notation was invented to capture this information in one glance. A round bracket ( or ) means "this endpoint is not included" (open interval). A square bracket [ or ] means "this endpoint is included" (closed interval). The smaller number always goes on the left.

Watch out

A common mistake is to reverse the brackets. Remember: the bracket faces outward (like () when the endpoint is excluded, and faces inward (like [) when the endpoint is included. Also, never write [6,−4)[6, -4) — the smaller number must always come first.

Step-by-Step Solutions

1. (i) {x:x∈R,−4<x≤6}\{x : x \in \mathbb{R}, -4 < x \leq 6\}

Look at the left end: −4<x-4 < x. The number −4-4 is not in the set. So we use a round bracket: (−4(-4.

Look at the right end: x≤6x \leq 6. The number 66 is in the set. So we use a square bracket: 6]6].

Put them together: (−4,6](-4, 6].

2. (ii) {x:x∈R,−12<x<−10}\{x : x \in \mathbb{R}, -12 < x < -10\}

Left end: −12<x-12 < x means −12-12 is not included → round bracket: (−12(-12.

Right end: x<−10x < -10 means −10-10 is not included → round bracket: −10)-10).

Together: (−12,−10)(-12, -10). …

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